用access做应用程序,往往做成"数据"和"程序"两个数据库,"数据"数据库中只存放数据表,"程序"数据库中存放所有的form,query,report,module等,通过表联接"程序"数据库可以访问所有"数据"数据库中的表。
当我们的应用程序更换存储位置的时候往往失去正确的表联接,造成运行错误。下面的一段程序可以自动找回表联接。在我的应用中"程序"数据库名字是stockMgr.mdb,"数据"数据库名字是stock-Data.mdb 注意:该程序仅限于"程序"和"数据"存放在同一个目录而且是对应单个"数据"文件的情况。
Function ReAttachTable() Dim MyDB As Database, MyTbl As TableDef Dim cpath As String Dim datafiles As String, i As Integer
On Error Resume Next Set MyDB = CurrentDb cpath = trimFileName(CurrentDb.Name) datafiles = "stock-data.mdb" DoCmd.Hourglass True For i = 0 To MyDB.TableDefs.Count - 1 Set MyTbl = MyDB.TableDefs(i) If MyTbl.Attributes = DB_ATTACHEDTABLE And Left(MyTbl.Connect, 1) = ";" Then MyTbl.Connect = ";DATABASE=" & cpath & datafiles MyTbl.RefreshLink If Err Then If vbNo = MsgBox(Err.description & ",继续吗?", vbYesNo) Then Exit For End If End If Next i DoCmd.Hourglass False msgbox "Tables relink finish." End Function
'绝对路径中去掉文件名,返回路径 Function trimFileName(fullname As String) As String Dim slen As Long, i As Long slen = Len(fullname) For i = slen To 1 Step -1 If Mid(fullname, i, 1) = "\" Then Exit For End If Next trimFileName = Left(fullname, i) End Function
在程序启动或者按钮动作中调用即可。 |